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x^2+17x+40=0
a = 1; b = 17; c = +40;
Δ = b2-4ac
Δ = 172-4·1·40
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{129}}{2*1}=\frac{-17-\sqrt{129}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{129}}{2*1}=\frac{-17+\sqrt{129}}{2} $
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